"what is the maximum allowed vcg" How to?

Professional Mariner Forum
1

I apologize in advance if this post should be in a different area of the forums. I’m taking my deck safety exam tomorrow, so I’m trying to figure this out asap :slight_smile:

How do you solve this problem?

You have 590 tons of below deck tonnage. No liquid mud. 84 tons of cargo above deck with a vcg above deck of 2.7 feet, what is the maximum allowed vcg of the remainder of the deck cargo that is permitted? Illustration d036dg

I know how to use the diagram to determine tonnage, but not vcg. Any help is appreciated! Thanks in advance!

2

It would be helpful if you provided the problem word for word. Without reading the entire question, which is usually a problem, is the answer 3.12 feet?

3

I don’t really understand what you are saying there? Yes that is the correct answer though…c. 3.11 feet

Is the solution easily explainable on here? If so thanks in advance!

4

Information from the problem:

The stability letter for the Hudson says that vertical center of gravity for cargo on deck cannot exceed 3 feet. And, without liquid mud, you cannot have more than 300 long tons of deck cargo. You have 84 tons of deck cargo.

Solution: You can [B]a[[/B]B]dd another 216 tons of deck cargo[/B], as long as the average vertical center of gravity does not exceed 3 feet. Think of it this way: You can put (300 tons x 3 feet average vcg) 900 average foot-tons of deck cargo onboard. You have already put on (84 tons x 2.7’ vcg) 226.8 average vcg foot-tons. Therefore, you can [B]add another 673.2 average foot-tons[/B] (900 - 226.8) of cargo on deck.

673.2 foot-tons divided by 216 tons = 3.117 average vcg

5

I’m posting from my phone (no computer Internet access here) and studying from the hawsepipe cd so sorry to not post all of the information!

That’s a great, simple way to think of it. Thanks a million for the breakdown and the help!