# Not for License Exam Fuel Consumption

**URL:** <https://forum.gcaptain.com/t/not-for-license-exam-fuel-consumption/54124>\
**Category:** Professional Mariner Forum\
**Created:** [February 8, 2020, 2:21am UTC](https://forum.gcaptain.com/t/not-for-license-exam-fuel-consumption/54124 "2020-02-08T02:21:07Z")\
**Posts on this page:** 1\
**Showing post:** 16

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**Author:** ![shipengr](https://sea2.discourse-cdn.com/flex016/user_avatar/forum.gcaptain.com/shipengr/32/485_2.png) [@shipengr](https://forum.gcaptain.com/u/shipengr)\
**Post date:** [February 7, 2020, 1:21am UTC](https://forum.gcaptain.com/t/not-for-license-exam-fuel-consumption/54124/16 "2020-02-07T01:21:09Z")

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> [@Captshane](#):
>
> were did u find the amount of bbls being burned. Is it in the merchant marine officers handbook ?

Ahh, sure. With the understanding that this is _purely academic_… **if the Exams ask you use the equation KC listed where Con1=Cons2 then use that.**

But for the realistic version using the first formula con2/con1= (v2/v1)^3 :

1. You already had the information that 17.5kt burns 274bbl/d. Using that and the first formula you can solve for the consumption at 17kt. This comes to 251bbl/d
2. You said you’re going 775nm at 17kt. So 17kt = 17nm/hr. 775nm divided by 17nm/hr = 45.6 hr. 45.6 hr divided by 24hr/day = 1.89 days
3. 251bbl/day multiplied by 1.89 days = 477 bbl

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